What is the domain of f(x)=(-12(3x^2+4))/((x^2-4)^3) ?

The domain of f(x)=(-12(3x^2+4))/((x^2-4)^3) is x 2

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domain of f(x)=(-12(3x^2+4))/((x^2-4)^3)

domain

f (x) = \frac{- 12 ( 3 x ^{2} + 4 )}{( x ^{2} - 4 ) ^{3}}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = ln (x + x^{2} - 1)

f (x) = \frac{x + 7}{2}

f (x) = lo g_{10} (14 - x)

+ ln (x) + ln (7 - x)

\frac{x - 1}{2 x - 3}

What is the domain of f(x)=(-12(3x^2+4))/((x^2-4)^3) ?
The domain of f(x)=(-12(3x^2+4))/((x^2-4)^3) is x<-2\lor-2<x<2\lor x>2