What is the domain of f(x)=ln(x+sqrt(x^2-1)) ?

The domain of f(x)=ln(x+sqrt(x^2-1)) is x>= 1

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domain of f(x)=ln(x+sqrt(x^2-1))

domain

f (x) = ln (x + x^{2} - 1)

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find positive values for logs:

x \geq 1

The function domain

x \geq 1

f (x) = \frac{x + 7}{2}

f (x) = lo g_{10} (14 - x)

+ ln (x) + ln (7 - x)

\frac{x - 1}{2 x - 3}

\frac{5}{x + 2} - \frac{1}{x ^{2} + x}

What is the domain of f(x)=ln(x+sqrt(x^2-1)) ?
The domain of f(x)=ln(x+sqrt(x^2-1)) is x>= 1