What is the domain of 5/(x+2)-1/(x^2+x) ?

The domain of 5/(x+2)-1/(x^2+x) is x 0

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domain of 5/(x+2)-1/(x^2+x)

domain

\frac{5}{x + 2} - \frac{1}{x ^{2} + x}

x < - 2 or - 2 < x < - 1 or - 1 < x < 0 or x > 0

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2, x = 0, x = - 1

The function domain

x < - 2 or - 2 < x < - 1 or - 1 < x < 0 or x > 0

2 x + 2

f (x) = \frac{\frac{x}{x + 1}}{\frac{1}{x}}

f (x) = \frac{2 x ^{2} + 6 x + 4}{- 3 x - 5}

f (x) = \frac{x - 4}{x ^{2} + x - 20}

2 x - 3

What is the domain of 5/(x+2)-1/(x^2+x) ?
The domain of 5/(x+2)-1/(x^2+x) is x<-2\lor-2<x<-1\lor-1<x<0\lor x>0