What is the domain of f(x)=sqrt(x^2+2x+9) ?

The domain of f(x)=sqrt(x^2+2x+9) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+2x+9)

domain

f (x) = x^{2} + 2 x + 9

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

100 - (x + 5)^{2}

f (x) = x^{2} + 10 x + 24

4 x - 4

4 x - 6

f (x) = - 2 x^{2} + 16 x - 31

What is the domain of f(x)=sqrt(x^2+2x+9) ?
The domain of f(x)=sqrt(x^2+2x+9) is -infinity <x<infinity