What is the domain of 1/(\sqrt[4]{x^2-4x)} ?

The domain of 1/(\sqrt[4]{x^2-4x)} is x 4

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domain of 1/(\sqrt[4]{x^2-4x)}

domain

x < 0 or x > 4

Interval Notation

(- \infty, 0) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

Find undefined (singularity) points:

x = 4, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 4

y = e^{\frac{1}{x}}

y = x 4 - x

\frac{1}{1 + x}

\frac{e ^{x} - 3}{5}

f (x) = 2 + 6 + 9 x

What is the domain of 1/(\sqrt[4]{x^2-4x)} ?
The domain of 1/(\sqrt[4]{x^2-4x)} is x<0\lor x>4