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Popular >

range of f(x)=-2x^2+8x-5

Solution

range

f (x) = - 2 x^{2} + 8 x - 5

Solution

f (x) \leq 3

+1

Interval Notation

(- \infty, 3]

Solution steps

Vertex of

- 2 x^{2} + 8 x - 5 :

Maximum

(2, 3)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 2,

Vertex

(x_{v}, y_{v}) = (2, 3)

f (x) \leq 3

Popular Examples

domain of f(x)=sqrt(x^2+x-6)domain

f (x) = x^{2} + x - 6

perpendicular 2x+3y=6 perpendicular

2 x + 3 y = 6

domain of f(x)=5+sqrt(x-2)domain

f (x) = 5 + x - 2

inverse of f(x)=\sqrt[3]{(-x+1)/2}inverse

domain of f(x)=(x+2)/(x^2-4x+4)domain

f (x) = \frac{x + 2}{x ^{2} - 4 x + 4}

Frequently Asked Questions (FAQ)

What is the range of f(x)=-2x^2+8x-5 ?
The range of f(x)=-2x^2+8x-5 is f(x)<= 3