What is the domain of f(x)=(sqrt(x))/(x^2-4) ?

The domain of f(x)=(sqrt(x))/(x^2-4) is 0 2

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domain of f(x)=(sqrt(x))/(x^2-4)

domain

f (x) = \frac{x}{x ^{2} - 4}

0 \leq x < 2 or x > 2

Interval Notation

[0, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

0 \leq x < 2 or x > 2

f (x) = \frac{2 - x}{x + 1}

f (x) = \frac{x ^{2} - 4}{x ^{2} + 1}

x^{2} - 6 x + 8

y = \frac{4}{3} x + 7 - 5

\frac{5 x}{8 x - 1}

What is the domain of f(x)=(sqrt(x))/(x^2-4) ?
The domain of f(x)=(sqrt(x))/(x^2-4) is 0<= x<2\lor x>2