What is the domain of f(x)=(2x-1)/(x^2-1) ?

The domain of f(x)=(2x-1)/(x^2-1) is x 1

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domain of f(x)=(2x-1)/(x^2-1)

domain

f (x) = \frac{2 x - 1}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

y = \frac{3 x + 4}{- 2 x + 6}

\frac{x ^{2} - 3 x + 2}{x ^{2} - 4}

f (x) = x^{2} + x

f (x) = \frac{2 x ^{2} - 6 x}{x ^{2} - 2 x - 3}

f (x) = 2 x + 2

What is the domain of f(x)=(2x-1)/(x^2-1) ?
The domain of f(x)=(2x-1)/(x^2-1) is x<-1\lor-1<x<1\lor x>1