What is the domain of f(x)= 3/(cos(x)-1)+10 ?

The domain of f(x)= 3/(cos(x)-1)+10 is 2pin<x<2pi+2pin

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domain of f(x)= 3/(cos(x)-1)+10

domain

f (x) = \frac{3}{cos ( x ) - 1} + 10

2 πn < x < 2 π + 2 πn

Interval Notation

(2 πn, 2 π + 2 πn)

Solution steps

Take the denominator(s) of

\frac{3}{cos ( x ) - 1} + 10

and compare to zero:

x = 2 πn

Periodicity of

\frac{3}{cos ( x ) - 1} + 10 : 2 π

Combine period:

2 πn \leq x < 2 π + 2 πn

and undefined points.

The domain is

2 πn < x < 2 π + 2 πn

f (x) = \frac{1}{4 - t ^{2}}

f (x) = ln (2 - x) + 1

f (x) = \frac{( x + 6 ) ^{2}}{8 x - 7}

f (x) = - sin (x)

\frac{x ^{2} - 16}{x ^{2} - 81}

What is the domain of f(x)= 3/(cos(x)-1)+10 ?
The domain of f(x)= 3/(cos(x)-1)+10 is 2pin<x<2pi+2pin