What is the domain of f(x)=((x+6)^2)/(sqrt(8x-7)) ?

The domain of f(x)=((x+6)^2)/(sqrt(8x-7)) is x> 7/8

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domain of f(x)=((x+6)^2)/(sqrt(8x-7))

domain

f (x) = \frac{( x + 6 ) ^{2}}{8 x - 7}

x > \frac{7}{8}

Interval Notation

(\frac{7}{8}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{7}{8}

Find undefined (singularity) points:

x = \frac{7}{8}

Combine real regions and undefined points for final function domain

x > \frac{7}{8}

f (x) = - sin (x)

\frac{x ^{2} - 16}{x ^{2} - 81}

f (x) = 9 cot (2 x - \frac{π}{2}) - 3

f (x) = \frac{( x - 2 )}{x ^{2}}

f (x) = \frac{x ^{2} - 9}{x ^{3} - 9 x}

What is the domain of f(x)=((x+6)^2)/(sqrt(8x-7)) ?
The domain of f(x)=((x+6)^2)/(sqrt(8x-7)) is x> 7/8