What is the domain of f(x)=9cot(2x-pi/2)-3 ?

The domain of f(x)=9cot(2x-pi/2)-3 is pi/2 n<= x< pi/4+pi/2 n\lor pi/4+pi/2 n<x< pi/2+pi/2 n

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domain of f(x)=9cot(2x-pi/2)-3

domain

f (x) = 9 cot (2 x - \frac{π}{2}) - 3

\frac{π}{2} n \leq x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

Interval Notation

[\frac{π}{2} n, \frac{π}{4} + \frac{π}{2} n) \cup (\frac{π}{4} + \frac{π}{2} n, \frac{π}{2} + \frac{π}{2} n)

Solution steps

Take the denominator(s) of

9 cot (2 x - \frac{π}{2}) - 3

and compare to zero:

x = \frac{π}{4} + \frac{π}{2} n

Periodicity of

9 cot (2 x - \frac{π}{2}) - 3 : \frac{π}{2}

Combine period:

\frac{π}{2} n \leq x < \frac{π}{2} + \frac{π}{2} n

and undefined points.

The domain is

\frac{π}{2} n \leq x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

f (x) = \frac{( x - 2 )}{x ^{2}}

f (x) = \frac{x ^{2} - 9}{x ^{3} - 9 x}

f (x) = \frac{5}{x ^{2}}

\frac{x + 7}{x - 5}

f (x) = 25 - x^{2} - 2

What is the domain of f(x)=9cot(2x-pi/2)-3 ?
The domain of f(x)=9cot(2x-pi/2)-3 is pi/2 n<= x< pi/4+pi/2 n\lor pi/4+pi/2 n<x< pi/2+pi/2 n