What is the domain of f(x)=ln((2x)/(x+1)) ?

The domain of f(x)=ln((2x)/(x+1)) is x 0

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domain of f(x)=ln((2x)/(x+1))

domain

f (x) = ln (\frac{2 x}{x + 1})

x < - 1 or x > 0

Interval Notation

(- \infty, - 1) \cup (0, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 0

\frac{x + 1}{x ^{2}}

h (x) = x + 16

ln (x - 7)

ln (x - 9)

f (x) = - 0. 2^{2 - x} - 2

What is the domain of f(x)=ln((2x)/(x+1)) ?
The domain of f(x)=ln((2x)/(x+1)) is x<-1\lor x>0