What is the domain of (9x-36)/(x^2+7x-18) ?

The domain of (9x-36)/(x^2+7x-18) is x 2

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domain of (9x-36)/(x^2+7x-18)

domain

\frac{9 x - 36}{x ^{2} + 7 x - 18}

x < - 9 or - 9 < x < 2 or x > 2

Interval Notation

(- \infty, - 9) \cup (- 9, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 9

The function domain

x < - 9 or - 9 < x < 2 or x > 2

f (x) = \frac{x - 1}{x - 1}

f (x) = 2 x^{2} - 7 x - 15

arcsin (x^{2})

f (x) = e^{x} - 5

y = \frac{1}{2} x + 5

What is the domain of (9x-36)/(x^2+7x-18) ?
The domain of (9x-36)/(x^2+7x-18) is x<-9\lor-9<x<2\lor x>2