What is the domain of f(x)=-3+log_{2}(x+1) ?

The domain of f(x)=-3+log_{2}(x+1) is x>-1

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domain of f(x)=-3+log_{2}(x+1)

domain

f (x) = - 3 + lo g_{2} (x + 1)

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find positive values for logs:

x > - 1

The function domain

x > - 1

(\frac{1}{6})^{x}

f (x) = 3 + ln (x)

\frac{x - 6}{2 x + 3}

f (x) = \frac{1 + x - 3 x ^{2}}{x x ^{2} - 4}

(x - 3)^{2} + 4

What is the domain of f(x)=-3+log_{2}(x+1) ?
The domain of f(x)=-3+log_{2}(x+1) is x>-1