What is the domain of f(x)=2x^3-3x^2+6,-1<= x<= 1 ?

The domain of f(x)=2x^3-3x^2+6,-1<= x<= 1 is -1<= x<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=2x^3-3x^2+6,-1<= x<= 1

domain

f (x) = 2 x^{3} - 3 x^{2} + 6, - 1 \leq x \leq 1

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Set the domain to the given interval

- 1 \leq x \leq 1

The function has no undefined points nor domain constraints. Therefore, the domain is

- 1 \leq x \leq 1

f (x) = x^{2} - 2 x + 6

y = ln (27 + 8 x^{3})

f (x) = (x - 1) + 1

f (x) = \frac{3 ^{2 x + 1}}{4}

f (x) = \frac{5 x ^{2} + 7 x - 13}{3 x ^{2} + 5 x - 2}

What is the domain of f(x)=2x^3-3x^2+6,-1<= x<= 1 ?
The domain of f(x)=2x^3-3x^2+6,-1<= x<= 1 is -1<= x<= 1