What is the domain of y=(18-2x)/(x^2-3x)-6/(3-x) ?

The domain of y=(18-2x)/(x^2-3x)-6/(3-x) is x 3

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domain of y=(18-2x)/(x^2-3x)-6/(3-x)

domain

y = \frac{18 - 2 x}{x ^{2} - 3 x} - \frac{6}{3 - x}

x < 0 or 0 < x < 3 or x > 3

Interval Notation

(- \infty, 0) \cup (0, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 0

The function domain

x < 0 or 0 < x < 3 or x > 3

cot (3 θ)

\frac{x ^{2} - 12}{2 x}

7 x^{2} + 3 x - 1

f (x) = \frac{x - 2}{2 x ^{2} + x - 10}

f (x) = \frac{x - 4}{2 x + 2}

What is the domain of y=(18-2x)/(x^2-3x)-6/(3-x) ?
The domain of y=(18-2x)/(x^2-3x)-6/(3-x) is x<0\lor 0<x<3\lor x>3