What is the domain of f(x)=(2x+1)/(sqrt(2x-1)) ?

The domain of f(x)=(2x+1)/(sqrt(2x-1)) is x> 1/2

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domain of f(x)=(2x+1)/(sqrt(2x-1))

domain

f (x) = \frac{2 x + 1}{2 x - 1}

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x > \frac{1}{2}

arcsin (\frac{1}{2} 2 - x)

(\frac{x}{2})^{2} + \frac{1}{x}

f (x) = \frac{10}{x} (4 - x)

f (x) = 4 x + 16

f (x) = - 3 - x + 1

What is the domain of f(x)=(2x+1)/(sqrt(2x-1)) ?
The domain of f(x)=(2x+1)/(sqrt(2x-1)) is x> 1/2