What is the domain of f(x)=sqrt(4x+16) ?

The domain of f(x)=sqrt(4x+16) is x>=-4

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domain of f(x)=sqrt(4x+16)

domain

f (x) = 4 x + 16

x \geq - 4

Interval Notation

[- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

The function domain

x \geq - 4

f (x) = - 3 - x + 1

f (x) = 2 x^{2} - 3 x

f (x) = \frac{x ^{2} + 3 x - 1}{4 x ^{2} - 3 x - 1}

arccos (e^{x - 1}) + π

arctan^{x} (x)

What is the domain of f(x)=sqrt(4x+16) ?
The domain of f(x)=sqrt(4x+16) is x>=-4