What is the domain of (-2x^2+5x-1)/(2x-1) ?

The domain of (-2x^2+5x-1)/(2x-1) is x 1/2

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domain of (-2x^2+5x-1)/(2x-1)

domain

\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1}

x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}

The function domain

x < \frac{1}{2} or x > \frac{1}{2}

f (x) = x^{2} - 16 \cdot (x^{2} + x - 2)

\frac{x ^{3} - 27}{x}

x^{2} + 5 x - 6

- \frac{5 x}{x - 6}

y = \frac{3 x + 5}{x - 1}

What is the domain of (-2x^2+5x-1)/(2x-1) ?
The domain of (-2x^2+5x-1)/(2x-1) is x< 1/2 \lor x> 1/2