What is the domain of f(x)=3+sqrt(2x-1) ?

The domain of f(x)=3+sqrt(2x-1) is x>= 1/2

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domain of f(x)=3+sqrt(2x-1)

domain

f (x) = 3 + 2 x - 1

x \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

The function domain

x \geq \frac{1}{2}

f (x) = \frac{x}{x ^{2} + 5 x + 6}

f (x) = \frac{3 x - 9}{x - 4}

f (x) = \frac{2 x + 3}{5 x + 4}

f (x) = \frac{x + 3}{x ^{2} - 5 x}

\frac{3}{4}

What is the domain of f(x)=3+sqrt(2x-1) ?
The domain of f(x)=3+sqrt(2x-1) is x>= 1/2