What is the domain of f(x)=(x+3)/(x^2-5x) ?

The domain of f(x)=(x+3)/(x^2-5x) is x 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x+3)/(x^2-5x)

domain

f (x) = \frac{x + 3}{x ^{2} - 5 x}

x < 0 or 0 < x < 5 or x > 5

Interval Notation

(- \infty, 0) \cup (0, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = 0

The function domain

x < 0 or 0 < x < 5 or x > 5

\frac{3}{4}

f (x) = ln (3 - 2 x)

f (x) = 6 ln (x)

f (x) = \frac{1}{2 x - 4}

f (x) = \frac{x - 9}{x ^{2} - 64}

What is the domain of f(x)=(x+3)/(x^2-5x) ?
The domain of f(x)=(x+3)/(x^2-5x) is x<0\lor 0<x<5\lor x>5