What is the domain of f(x)=((-2(x^2-1)))/((x^2-4)) ?

The domain of f(x)=((-2(x^2-1)))/((x^2-4)) is x 2

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domain of f(x)=((-2(x^2-1)))/((x^2-4))

domain

f (x) = \frac{( - 2 ( x ^{2} - 1 ) )}{( x ^{2} - 4 )}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = e^{z} + 4 x^{2} + 9 y^{2} = 1

f (x) = \frac{3 x ^{2} - 2 x - 8}{x ^{2} + 3 x - 10}

y = 8 x - 2

2 cos (3 x + π)

lo g_{10} (2) (x + 2) + 5

What is the domain of f(x)=((-2(x^2-1)))/((x^2-4)) ?
The domain of f(x)=((-2(x^2-1)))/((x^2-4)) is x<-2\lor-2<x<2\lor x>2