What is the domain of f(x)=(sqrt(x-3))/(sqrt(x^2-9)) ?

The domain of f(x)=(sqrt(x-3))/(sqrt(x^2-9)) is x>3

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domain of f(x)=(sqrt(x-3))/(sqrt(x^2-9))

domain

f (x) = \frac{x - 3}{x ^{2} - 9}

x > 3

Interval Notation

(3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x > 3

f (x) = \frac{2 x ^{2} + 5}{x ^{2} - 25}

\frac{7}{x ^{2} - 14 x - 32}

f (x) = 3 (2^{x})

f (x) = 15 cos (3 x - \frac{3 π}{5}) - 7

f (x) = \frac{3 x}{7 x - 5}

What is the domain of f(x)=(sqrt(x-3))/(sqrt(x^2-9)) ?
The domain of f(x)=(sqrt(x-3))/(sqrt(x^2-9)) is x>3