What is the domain of f(x)=(2x^2+5)/(x^2-25) ?

The domain of f(x)=(2x^2+5)/(x^2-25) is x 5

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domain of f(x)=(2x^2+5)/(x^2-25)

domain

f (x) = \frac{2 x ^{2} + 5}{x ^{2} - 25}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

\frac{7}{x ^{2} - 14 x - 32}

f (x) = 3 (2^{x})

f (x) = 15 cos (3 x - \frac{3 π}{5}) - 7

f (x) = \frac{3 x}{7 x - 5}

\frac{x}{x + 1}

What is the domain of f(x)=(2x^2+5)/(x^2-25) ?
The domain of f(x)=(2x^2+5)/(x^2-25) is x<-5\lor-5<x<5\lor x>5