What is the domain of x/(sqrt(x+1)) ?

The domain of x/(sqrt(x+1)) is x>-1

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domain of x/(sqrt(x+1))

domain

\frac{x}{x + 1}

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x > - 1

\frac{x ^{2} + 6}{3 x ^{2} - 12 x - 15}

arccos (x^{2})

f (x) = \frac{4}{( x ^{2} - 9 )}

3^{x} + 4

f (x) = \frac{6 x - 25}{- 5 x + 41}