What is the domain of f(x)= 4/((x^2-9)) ?

The domain of f(x)= 4/((x^2-9)) is x 3

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domain of f(x)= 4/((x^2-9))

domain

f (x) = \frac{4}{( x ^{2} - 9 )}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

3^{x} + 4

f (x) = \frac{6 x - 25}{- 5 x + 41}

f (x) = \frac{x + 4}{x - 6}

e^{- 2 x}

f (x) = \frac{x + 4}{x - 1}

What is the domain of f(x)= 4/((x^2-9)) ?
The domain of f(x)= 4/((x^2-9)) is x<-3\lor-3<x<3\lor x>3