What is the domain of f(x)= 1/(((2x-9)(x+1))) ?

The domain of f(x)= 1/(((2x-9)(x+1))) is x 9/2

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domain of f(x)= 1/(((2x-9)(x+1)))

domain

f (x) = \frac{1}{( ( 2 x - 9 ) ( x + 1 ) )}

x < - 1 or - 1 < x < \frac{9}{2} or x > \frac{9}{2}

Interval Notation

(- \infty, - 1) \cup (- 1, \frac{9}{2}) \cup (\frac{9}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{9}{2}, x = - 1

The function domain

x < - 1 or - 1 < x < \frac{9}{2} or x > \frac{9}{2}

\frac{4 x}{5 x - 1}

f (x) = \frac{2 x + 1}{3 x - 8}

f (x) = x^{2} + 2 x - 3, - 4 \leq x \leq 4

f (x) = 7 - 4 x

- x^{2} + 2 x + 1

What is the domain of f(x)= 1/(((2x-9)(x+1))) ?
The domain of f(x)= 1/(((2x-9)(x+1))) is x<-1\lor-1<x< 9/2 \lor x> 9/2