What is the domain of f(x)=(2x+1)/(3x-8) ?

The domain of f(x)=(2x+1)/(3x-8) is x 8/3

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domain of f(x)=(2x+1)/(3x-8)

domain

f (x) = \frac{2 x + 1}{3 x - 8}

x < \frac{8}{3} or x > \frac{8}{3}

Interval Notation

(- \infty, \frac{8}{3}) \cup (\frac{8}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{8}{3}

The function domain

x < \frac{8}{3} or x > \frac{8}{3}

f (x) = x^{2} + 2 x - 3, - 4 \leq x \leq 4

f (x) = 7 - 4 x

- x^{2} + 2 x + 1

f (x) = \frac{x + 4}{x + 5}

f (x) = \frac{x + 1}{x - 5}

What is the domain of f(x)=(2x+1)/(3x-8) ?
The domain of f(x)=(2x+1)/(3x-8) is x< 8/3 \lor x> 8/3