What is the domain of y= x/(x^2+16) ?

The domain of y= x/(x^2+16) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y= x/(x^2+16)

domain

y = \frac{x}{x ^{2} + 16}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

- 9

f (x) = \frac{\frac{6}{x}}{\frac{1}{x ^{2} - 1}}

3 t

f (x) = \frac{x - 1}{x - 4}

2 (x - 1)^{2} - 3

What is the domain of y= x/(x^2+16) ?
The domain of y= x/(x^2+16) is -infinity <x<infinity