What is the domain of f(x)=2x-3+sqrt(x-1) ?

The domain of f(x)=2x-3+sqrt(x-1) is x>= 1

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domain of f(x)=2x-3+sqrt(x-1)

domain

f (x) = 2 x - 3 + x - 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

\frac{∣ x + 5 ∣ - 2}{x - 3}

f (x) = \frac{6 x - 2}{8 x + 8}

4 - 3 - x

\frac{x - 4}{5}

\frac{1 + 1 - 4 x ^{2}}{2 x}

What is the domain of f(x)=2x-3+sqrt(x-1) ?
The domain of f(x)=2x-3+sqrt(x-1) is x>= 1