What is the domain of y=(x-3)/(sqrt(x-2)) ?

The domain of y=(x-3)/(sqrt(x-2)) is x>2

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domain of y=(x-3)/(sqrt(x-2))

domain

y = \frac{x - 3}{x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

\frac{2 x}{x ^{2} + 2}

f (x) = \frac{x - 4}{25 - x ^{2}}

\frac{3 x + 8}{x - 2}

\frac{3 x + 2}{2 x - 5}

f (x) = x y^{2} - x + 3 y^{2} + 1 = 0

What is the domain of y=(x-3)/(sqrt(x-2)) ?
The domain of y=(x-3)/(sqrt(x-2)) is x>2