What is the domain of f(x)=(x-4)/(sqrt(25-x^2)) ?

The domain of f(x)=(x-4)/(sqrt(25-x^2)) is -5<x<5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x-4)/(sqrt(25-x^2))

domain

f (x) = \frac{x - 4}{25 - x ^{2}}

- 5 < x < 5

Interval Notation

(- 5, 5)

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

Find undefined (singularity) points:

x = 5, x = - 5

Combine real regions and undefined points for final function domain

- 5 < x < 5

\frac{3 x + 8}{x - 2}

\frac{3 x + 2}{2 x - 5}

f (x) = x y^{2} - x + 3 y^{2} + 1 = 0

f (x) = - 5 x + 9

f (x) = \frac{ln ( 4 - x ^{2} )}{e ^{x} - 1}

What is the domain of f(x)=(x-4)/(sqrt(25-x^2)) ?
The domain of f(x)=(x-4)/(sqrt(25-x^2)) is -5<x<5