What is the domain of f(x)=(ln(4-x^2))/(e^x-1) ?

The domain of f(x)=(ln(4-x^2))/(e^x-1) is -2<x<0\lor 0<x<2

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domain of f(x)=(ln(4-x^2))/(e^x-1)

domain

f (x) = \frac{ln ( 4 - x ^{2} )}{e ^{x} - 1}

- 2 < x < 0 or 0 < x < 2

Interval Notation

(- 2, 0) \cup (0, 2)

Solution steps

Find positive values for logs:

- 2 < x < 2

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 2 < x < 0 or 0 < x < 2

f (x) = \frac{x - 5}{2 x - 3}

y = 1 - ln (x^{2} - 1)

f (x) = \frac{( x + 1 ) ( x + 2 )}{x - 3}

f (x) = 4 sin (x) cos (x)

10 - x^{2}

What is the domain of f(x)=(ln(4-x^2))/(e^x-1) ?
The domain of f(x)=(ln(4-x^2))/(e^x-1) is -2<x<0\lor 0<x<2