What is the domain of y=arccos(1/(x-3)) ?

The domain of y=arccos(1/(x-3)) is x = 4

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domain of y=arccos(1/(x-3))

domain

y = arccos (\frac{1}{x - 3})

x \leq 2 or x \geq 4

Interval Notation

(- \infty, 2] \cup [4, \infty)

Solution steps

Find known functions domain restrictions:

x \leq 2 or x \geq 4

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x \leq 2 or x \geq 4

f (x) = \frac{2}{1 - cos ( x )}

f (x) = \frac{( 5 ln ( x ) )}{x ^{3}}

\frac{x ^{2} - 2}{x ^{2} - 4}

ln (e^{x} - 8) + 5

f (x) = \frac{5 t + 1}{t ^{3} - t ^{2} - 8 t}

What is the domain of y=arccos(1/(x-3)) ?
The domain of y=arccos(1/(x-3)) is x<= 2\lor x>= 4