What is the domain of y= 1/2 tan(2x) ?

The domain of y= 1/2 tan(2x) is pi/2 n<= x< pi/4+pi/2 n\lor pi/4+pi/2 n<x< pi/2+pi/2 n

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domain of y= 1/2 tan(2x)

domain

y = \frac{1}{2} tan (2 x)

\frac{π}{2} n \leq x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

Interval Notation

[\frac{π}{2} n, \frac{π}{4} + \frac{π}{2} n) \cup (\frac{π}{4} + \frac{π}{2} n, \frac{π}{2} + \frac{π}{2} n)

Solution steps

Take the denominator(s) of

\frac{1}{2} tan (2 x)

and compare to zero:

x = \frac{π}{4} + \frac{π}{2} n

Periodicity of

\frac{1}{2} tan (2 x) : \frac{π}{2}

Combine period:

\frac{π}{2} n \leq x < \frac{π}{2} + \frac{π}{2} n

and undefined points.

The domain is

\frac{π}{2} n \leq x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

f (x) = \frac{1}{9} x^{2}

\frac{2 x + 1}{3 x - 4}

y = \frac{3}{2} x^{2} - 3 x + 4

y = 2 x^{2} + 1

\frac{1}{2} x - 5

What is the domain of y= 1/2 tan(2x) ?
The domain of y= 1/2 tan(2x) is pi/2 n<= x< pi/4+pi/2 n\lor pi/4+pi/2 n<x< pi/2+pi/2 n