What is the domain of f(x)= 2/(3sqrt(x^2+9)) ?

The domain of f(x)= 2/(3sqrt(x^2+9)) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 2/(3sqrt(x^2+9))

domain

f (x) = \frac{2}{3 x ^{2} + 9}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = e^{2}

z

g

f (x) = \frac{x - 8}{x - 49}

f (x) = ln (\frac{1}{x + 8})

What is the domain of f(x)= 2/(3sqrt(x^2+9)) ?
The domain of f(x)= 2/(3sqrt(x^2+9)) is -infinity <x<infinity