What is the domain of f(x)= 1/(x^2+7x+6) ?

The domain of f(x)= 1/(x^2+7x+6) is x -1

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domain of f(x)= 1/(x^2+7x+6)

domain

f (x) = \frac{1}{x ^{2} + 7 x + 6}

x < - 6 or - 6 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 6) \cup (- 6, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 6

The function domain

x < - 6 or - 6 < x < - 1 or x > - 1

f (x) = \frac{1}{t + 1}

f (x) = 3 cos (2 x)

ln (\frac{x}{x ^{2} + 1})

y = \frac{x + 3}{2 x ^{2} - 2}

\frac{5 x - 1}{2 x + 3}

What is the domain of f(x)= 1/(x^2+7x+6) ?
The domain of f(x)= 1/(x^2+7x+6) is x<-6\lor-6<x<-1\lor x>-1