What is the domain of y=(2x^2)/(1-x^2) ?

The domain of y=(2x^2)/(1-x^2) is x 1

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domain of y=(2x^2)/(1-x^2)

domain

y = \frac{2 x ^{2}}{1 - x ^{2}}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = sin (x) + cos (x)

f (x) = \frac{x}{x + 1} + \frac{x + 1}{x + 2}

f (x) = \frac{25 - x ^{2}}{x ^{2} - 16}

f (x) = \frac{2 x}{36 - x}

lo g_{10} (x - 7)

What is the domain of y=(2x^2)/(1-x^2) ?
The domain of y=(2x^2)/(1-x^2) is x<-1\lor-1<x<1\lor x>1