What is the inverse of f(x)=log_{6}(x^2) ?

The inverse of f(x)=log_{6}(x^2) is sqrt(6^x),-sqrt(6^x)

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inverse of f(x)=log_{6}(x^2)

inverse

f (x) = lo g_{6} (x^{2})

6^{x}, - 6^{x}

Solution steps

y = lo g_{6} (x^{2})

Replace

x

with

y

x = lo g_{6} (y^{2})

Solve for

y, x = lo g_{6} (y^{2})

6^{x}, - 6^{x}

f (x) = 9 + 3 x^{2} - 2 x^{3}

f (x) = \frac{( 7 )}{( 2 ) sin ( θ )}

Y (x) = x^{2} - 6

What is the inverse of f(x)=log_{6}(x^2) ?
The inverse of f(x)=log_{6}(x^2) is sqrt(6^x),-sqrt(6^x)