What is the inverse of y=x^2+3x+2 ?

The inverse of y=x^2+3x+2 is (-3+sqrt(4x+1))/2 ,(-3-sqrt(4x+1))/2

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inverse of y=x^2+3x+2

inverse

y = x^{2} + 3 x + 2

\frac{- 3 + 4 x + 1}{2}, \frac{- 3 - 4 x + 1}{2}

Solution steps

y = x^{2} + 3 x + 2

Replace

x

with

y

x = y^{2} + 3 y + 2

Solve for

y, x = y^{2} + 3 y + 2

\frac{- 3 + 4 x + 1}{2}, \frac{- 3 - 4 x + 1}{2}

lo g_{a} (x^{2} - 4)

f (x) = 5 x^{2} ln (\frac{x}{2})

f (x) = \frac{x}{49 + x ^{2}}

f (x) = 3 x + 1

f (x) = 25 - x^{2} + x + 3

What is the inverse of y=x^2+3x+2 ?
The inverse of y=x^2+3x+2 is (-3+sqrt(4x+1))/2 ,(-3-sqrt(4x+1))/2