What is the domain of f(x)=9x^2+16y^2=4z^2 ?

The domain of f(x)=9x^2+16y^2=4z^2 is -infinity <z<infinity

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domain of f(x)=9x^2+16y^2=4z^2

domain

f (x) = 9 x^{2} + 16 y^{2} = 4 z^{2}

- \infty < z < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < z < \infty

f (x) = x - 3 x^{2}

f (x) = \frac{3 x - 1}{- 2 x - 6}

f (x) = - x + 1 + 2

f (x) = \frac{x ^{2} - 16}{18 - 2 x ^{2}}

f (x) = ln (3 x - 5)

What is the domain of f(x)=9x^2+16y^2=4z^2 ?
The domain of f(x)=9x^2+16y^2=4z^2 is -infinity <z<infinity