What is the domain of g(x)=sqrt(49-x^2) ?

The domain of g(x)=sqrt(49-x^2) is -7<= x<= 7

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domain of g(x)=sqrt(49-x^2)

domain

g (x) = 49 - x^{2}

- 7 \leq x \leq 7

Interval Notation

[- 7, 7]

Solution steps

Find non-negative values for radicals:

- 7 \leq x \leq 7

The function domain

- 7 \leq x \leq 7

csc (2 x)

f (x) = ∣ x - 1 ∣ - 1

\frac{( x ^{5} - 16 x )}{5 x ^{3} - 6 x ^{2} + x}

f (x) = ln (x - 2) - 1

\frac{6 x - 12}{( x - 6 ) ( x + 1 )}

What is the domain of g(x)=sqrt(49-x^2) ?
The domain of g(x)=sqrt(49-x^2) is -7<= x<= 7