What is the domain of g(x)= 1/(x^2-x) ?

The domain of g(x)= 1/(x^2-x) is x 1

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domain of g(x)= 1/(x^2-x)

domain

g (x) = \frac{1}{x ^{2} - x}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = 0

The function domain

x < 0 or 0 < x < 1 or x > 1

f (x) = \frac{( x ^{2} - x - 12 )}{25 - x ^{2}}

ln (8 - x^{3})

f (x) = ln (x^{2} + 2 x - 3)

8 + x

f (x) = 5 x 4 x - x^{2}

What is the domain of g(x)= 1/(x^2-x) ?
The domain of g(x)= 1/(x^2-x) is x<0\lor 0<x<1\lor x>1