What is the domain of (x^2+2x-24)/(x^2-2x-8) ?

The domain of (x^2+2x-24)/(x^2-2x-8) is x 4

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domain of (x^2+2x-24)/(x^2-2x-8)

domain

\frac{x ^{2} + 2 x - 24}{x ^{2} - 2 x - 8}

x < - 2 or - 2 < x < 4 or x > 4

Interval Notation

(- \infty, - 2) \cup (- 2, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 2

The function domain

x < - 2 or - 2 < x < 4 or x > 4

f (x) = \frac{x ^{2}}{7 - x}

f (x) = 8 + (ln (x^{2} - 25))^{2}

f (x) = x^{- 2}

f (x) = \frac{3}{2} x^{4} - 2 x^{3} - 6 x^{2} + 8

f (x) = (\frac{1}{7})^{x}

What is the domain of (x^2+2x-24)/(x^2-2x-8) ?
The domain of (x^2+2x-24)/(x^2-2x-8) is x<-2\lor-2<x<4\lor x>4