What is the extreme f(x)=6x^4+16x^3 ?

The extreme f(x)=6x^4+16x^3 is Minimum(-2,-32),Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=6x^4+16x^3

extreme points

f (x) = 6 x^{4} + 16 x^{3}

Minimum (- 2, - 32), Saddle (0, 0)

Solution steps

f^{'} (x) = 24 x^{3} + 48 x^{2}

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

6 x^{4} + 16 x^{3} : - 32

Minimum (- 2, - 32)

Plug

x = 0

into

6 x^{4} + 16 x^{3} : 0

Saddle (0, 0)

Minimum (- 2, - 32), Saddle (0, 0)

f (x) = e^{- x^{2}}

f (x) = 4 x - 12

f (x) = 2 x + 6

y = x - 6

(0, 0), (- 2, 3)

What is the extreme f(x)=6x^4+16x^3 ?
The extreme f(x)=6x^4+16x^3 is Minimum(-2,-32),Saddle(0,0)