What is the domain of f(x)= 1/(\sqrt[3]{4-2x)} ?

The domain of f(x)= 1/(\sqrt[3]{4-2x)} is x 2

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domain of f(x)= 1/(\sqrt[3]{4-2x)}

domain

x < 2 or x > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2

The function domain

x < 2 or x > 2

f (x) = cos (x^{2})

f (x) = \frac{x}{( x ^{2} - 9 )}

f (x) = \frac{x - 6}{x ^{2} - 25}

\frac{1728000000 x - 13824000000}{6}

3 y + x y = 2 x + 1

What is the domain of f(x)= 1/(\sqrt[3]{4-2x)} ?
The domain of f(x)= 1/(\sqrt[3]{4-2x)} is x<2\lor x>2