What is the domain of 1/(sin(x)cos(x)) ?

The domain of 1/(sin(x)cos(x)) is pin<x< pi/2+pin\lor pi/2+pin<x<pi+pin

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domain of 1/(sin(x)cos(x))

domain

\frac{1}{sin ( x ) cos ( x )}

πn < x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Interval Notation

(πn, \frac{π}{2} + πn) \cup (\frac{π}{2} + πn, π + πn)

Solution steps

Take the denominator(s) of

\frac{1}{sin ( x ) cos ( x )}

and compare to zero:

x = πn, x = \frac{π}{2} + πn

Periodicity of

\frac{1}{sin ( x ) cos ( x )} : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn < x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

f (x) = \frac{1}{49 - x ^{2}}

y = \frac{x + 2}{x}

\frac{1}{lo g _{x} ( 2 )}

f (x) = x - 2 + 2 - x

p (x) = x - 1 + 2

What is the domain of 1/(sin(x)cos(x)) ?
The domain of 1/(sin(x)cos(x)) is pin<x< pi/2+pin\lor pi/2+pin<x<pi+pin