What is the domain of f(x)=(x+1)/(x^2-4x) ?

The domain of f(x)=(x+1)/(x^2-4x) is x 4

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domain of f(x)=(x+1)/(x^2-4x)

domain

f (x) = \frac{x + 1}{x ^{2} - 4 x}

x < 0 or 0 < x < 4 or x > 4

Interval Notation

(- \infty, 0) \cup (0, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = 0

The function domain

x < 0 or 0 < x < 4 or x > 4

y = - (lo g_{2} (x)) + 3.16

+ y = 100 - x^{2}

f (x) = \frac{x + 4}{x}

f (x) = \frac{6 x ^{2} - x ^{4}}{9}

\frac{5}{x ^{2} - 1}

What is the domain of f(x)=(x+1)/(x^2-4x) ?
The domain of f(x)=(x+1)/(x^2-4x) is x<0\lor 0<x<4\lor x>4