What is the domain of+y=sqrt(100-x^2) ?

The domain of+y=sqrt(100-x^2) is -10<= x<= 10

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domain of+y=sqrt(100-x^2)

domain

+ y = 100 - x^{2}

- 10 \leq x \leq 10

Interval Notation

[- 10, 10]

Solution steps

Find non-negative values for radicals:

- 10 \leq x \leq 10

The function domain

- 10 \leq x \leq 10

f (x) = \frac{x + 4}{x}

f (x) = \frac{6 x ^{2} - x ^{4}}{9}

\frac{5}{x ^{2} - 1}

f (x) = 3^{x - 2} - 1

f (x) = - \frac{1}{2} \cdot lo g_{10} (- 2 - x) + 2

What is the domain of+y=sqrt(100-x^2) ?
The domain of+y=sqrt(100-x^2) is -10<= x<= 10