What is the domain of f(x)= 1/t+sqrt(4-t) ?

The domain of f(x)= 1/t+sqrt(4-t) is t<0\lor 0<t<= 4

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domain of f(x)= 1/t+sqrt(4-t)

domain

f (x) = \frac{1}{t} + 4 - t

t < 0 or 0 < t \leq 4

Interval Notation

(- \infty, 0) \cup (0, 4]

Solution steps

Find non-negative values for radicals:

t \leq 4

Find undefined (singularity) points:

t = 0

Combine real regions and undefined points for final function domain

t < 0 or 0 < t \leq 4

f (x) = lo g_{2} (2^{2 x})

\frac{1}{2 + x}

f (x) = \frac{2 x ^{2} - 13 x + 15}{x - 1}

2^{x + 2} + 1

\frac{1}{x - 2}

What is the domain of f(x)= 1/t+sqrt(4-t) ?
The domain of f(x)= 1/t+sqrt(4-t) is t<0\lor 0<t<= 4